第一篇:人教版八年級(jí)上冊(cè)英語(yǔ)(新目標(biāo))配套練習(xí)冊(cè)答案[小編推薦]
山東省
人教版八年級(jí)上冊(cè)英語(yǔ)(新目標(biāo))配套練習(xí)冊(cè)答案
Unit 1 How often do you exercise?
Section A I.1.program 2.results 3.Exercise 4.twice 5.Internet II.DBDDC ABC III.1.helps 2.skateboarding 3.once 4.active 5.shopping IV.1.surfs the Internet 2.goes to the movies 3.never arrives late 4.fours times a month 5.How often V.1.How often does go 2.What does do 3.Does go doesn’t 4.What do do 5.What is VI.CDAB
Section B I.1.different 2.health 3.habit 4.try 5.keep 6.Although 7.for 8.better II.DDCBA ADACD III.goes 2.eating 3.to esercise 4.get 5.to drink IV.1.healthy lifestyle 2.Of course,twice a week 3.How many 4.is good for 5.As for most V.DBDAC ACCAB VI.CBDCD BABCA VII.(略)Unit 2 What’s the matter ?
Section A I.1.matter 2.foot 3.toothache 3.mouth 5.headache 6.fever 7.rest 8.teeth II.DADCA ABA III.1.stomachache 2.ill 3.feet 4.better 5.backache IV.1.What’s matter with 2.should lie down rest 3.have a fever 4.with honer 5.not feiiing well 6.see a dentist
V.What’s the matter with 2.shouldn’t eat anything 3.Does have 4.When did it start 5.How is she felling VI.EGADC
Section B I.1.thirsty 2.stressed 3.early 4.problem 5.Traditional 6.weak 7.angry 8.westrn II.DCBBB AADCB III.1.to have ,to eat 2.exercise 3.enjoying 4.to hear 5.stressed IV.1.go to bed ,to stay healthy 2.too much 3.stressed out,angry 4.western countries 5.shouldn’t study V.BBADC AACDA VI.DCDCA VII.(略)
第二篇:人教版八年級(jí)上冊(cè)英語(yǔ)(新目標(biāo))配套練習(xí)冊(cè)答案
山東省
人教版八年級(jí)上冊(cè)英語(yǔ)(新目標(biāo))配套練習(xí)冊(cè)答案
Unit 1 How often do you exercise?
Section A I.1.program 2.results 3.Exercise 4.twice 5.Internet II.DBDDC ABC III.1.helps 2.skateboarding 3.once 4.active 5.shopping IV.1.surfs the Internet 2.goes to the movies 3.never arrives late 4.fours times a month 5.How often V.1.How often does go 2.What does do 3.Does go doesn’t 4.What do do 5.What is VI.CDAB
Section B I.1.different 2.health 3.habit 4.try 5.keep 6.Although 7.for 8.better II.DDCBA ADACD III.goes 2.eating 3.to esercise 4.get 5.to drink IV.1.healthy lifestyle 2.Of course,twice a week 3.How many 4.is good for 5.As for most V.DBDAC ACCAB VI.CBDCD BABCA VII.(略)Unit 2 What’s the matter ?
Section A I.1.matter 2.foot 3.toothache 3.mouth 5.headache 6.fever 7.rest 8.teeth II.DADCA ABA III.1.stomachache 2.ill 3.feet 4.better 5.backache IV.1.What’s matter with 2.should lie down rest 3.have a fever 4.with honer 5.not feiiing well 6.see a dentist
V.What’s the matter with 2.shouldn’t eat anything 3.Does have 4.When did it start 5.How is she felling VI.EGADC
Section B I.1.thirsty 2.stressed 3.early 4.problem 5.Traditional 6.weak 7.angry 8.westrn II.DCBBB AADCB III.1.to have ,to eat 2.exercise 3.enjoying 4.to hear 5.stressed IV.1.go to bed ,to stay healthy 2.too much 3.stressed out,angry 4.western countries 5.shouldn’t study V.BBADC AACDA VI.DCDCA VII.(略)學(xué)園救援團(tuán) 可愛(ài)旋律 瀨戶之花嫁
第三篇:八年級(jí)上冊(cè)配套練習(xí)冊(cè)答案
數(shù)學(xué)練習(xí)冊(cè)八年級(jí)上冊(cè)參考答案 1.1 1.略.2.DE,∠EDB,∠E.3.略.4.B5.C 6.AB=AC,BE=CD,AE=AD,∠BAE=∠CAD 7.AB∥EF,BC∥ED.8.(1)2a+2b;(2)2a+3b;(3)當(dāng)n為偶數(shù)時(shí),n2(a+b);當(dāng)n為奇數(shù)時(shí),n-12a+n+12b.1.2第1課時(shí)
1.D2.C3.(1)AD=AE;(2)∠ADB=∠AEC.4.∠1=∠25.△ABC≌△FDE(SAS)6.AB∥CD.因?yàn)椤鰽BO≌△CDO(SAS).∠A=∠C.7.BE=CD.因?yàn)椤鰽BE≌△ACD(SAS).第2課時(shí)
1.B2.D3.(1)∠ADE=∠ACB;(2)∠E=∠B.4.△ABD≌△BAC(AAS)5.(1)相等,因?yàn)椤鰽BE≌△CBD(ASA);(2)DF=EF,因?yàn)椤鰽DF≌△CEF(ASA).6.相等,因?yàn)椤鰽BC≌△ADC(AAS).7.(1)△ADC≌△AEB;(2)AC=AB,DC=EB,BD=EC;∠ABE=∠ACD,∠BDO=∠CEO,∠BOD=∠COE.第3課時(shí)
1.B2.C3.110°4.BC的中點(diǎn).因?yàn)椤鰽BD≌△ACD(SSS).5.正確.因?yàn)椤鱀EH≌△DFH(SSS).6.全等.因?yàn)椤鰽BD≌△ACD(SSS).∠BAF=∠CAF.7.相等,因?yàn)椤鰽BO≌△ACO(SSS).1.3第1課時(shí)
1~6(略).7.作∠AOB=∠α,延長(zhǎng)BO,在BO上取一點(diǎn)C,則∠AOC即為所求.8.作∠AOB=∠α,以O(shè)B為邊,在∠AOB的外部作∠BOC=∠β;再以O(shè)A為邊,在∠AOC的內(nèi)部作∠AOD=∠γ,則∠DOC即為所求.第2課時(shí)
1.略.2.(1)略;(2)全等(SAS).3.作BC=a-b;分別以點(diǎn)B、C為圓心,a為半徑畫(huà)弧,兩弧交于點(diǎn)A;連接AB,AC,△ABC即為所求.4.分四種情況:(1)頂角為∠α,腰長(zhǎng)為a;(2)底角為∠α,底邊為a;(3)頂角為∠α,底邊為a;(4)底角為∠α,腰長(zhǎng)為a.((3),(4)暫不作).第3課時(shí)
1.四種:SSS,SAS,ASA,AAS.2.作線段AB;作∠BAD=∠α,在∠BAD同側(cè)作∠ABE=∠B;AD與BE相交于點(diǎn)C.△ABC即為所求.3.作∠γ=∠α+∠β;作∠γ的外角∠γ′;作△ABC,使AB=c.∠A=∠γ′,∠B=∠α.4.作∠γ=180°-∠β;作△ABC,使BC=a,∠B=∠α,∠C=∠γ.第一章綜合練習(xí)
1.A2.C3.C4.AB=DC或∠ACB=∠DBC或∠A=∠D.5.△ACD≌△BDC,△ABC≌△BAC.6.△ABC≌△CDE(AAS)7.4分鐘8.△BOC′≌△B′OC(AAS)9.略10.相等.△BCF≌△EDF(SAS).△ABF≌△AEF(SSS)檢測(cè)站
1.B2.B3.20°4.∠BCD5.相等.△ABP≌△ACP(SSS),△PDB≌△PEC(AAS).6.略 2.1 1~3.略.4.B5.C6.(1)(2)(4)7.20°;30°.8.略
2.2第1課時(shí)
1~2.略3.C4.D5.略6.66°7.(1)AA′∥CC′∥BB′,且AA′⊥MN,BB′⊥MN,CC′⊥MN.(2)5 cm8.(1)DE⊥AF;(2)略.第2課時(shí) 1.(-2,-3),(2,3).2.3,-43.(3,2)4.B 5~6.略7.(1)(-a,b);(2)當(dāng)n=4k+1時(shí),在第一象限,n=4k+2時(shí),在第四象限,n=4k+3時(shí),在第三象限,n=4(n+1)時(shí),在第二象限,k為非負(fù)整數(shù).2.3 1~3.略.4.B5.C.6.略.7.4條.8.略.2.4第1課時(shí)
1.略.2.CM=DM,CE=DE.3.C4.∠A=∠B,∠ACD=∠BCD,∠ADC=∠BDC.5~6.略.7.連接BM,PB<PM+MB,∵M(jìn)B=MA,∴PB<PA.第2課時(shí)
1.作一條線段的垂直平分線2.D3~5.略.6.分別作點(diǎn)A關(guān)于OM,ON的對(duì)稱點(diǎn)D,E.連接DE,分別交OM,ON于點(diǎn)B,C.連接AB,AC,則△ABC的周長(zhǎng)最小.2.5 1.略.2.103.D4.C5.作∠AOB的平分線交MN于點(diǎn)P.則P即為所示.6.(1)DE=DC,AE=BE,BE=BC;(2)7.7.(1)△ADO≌△AEO(AAS),△BOD≌△COE(ASA),OB=OC;(2)∠1=∠2.8.4處.三條直線圍成的三角形的三內(nèi)角平分線的交點(diǎn),及任一內(nèi)角平分線與其他兩個(gè)角的外角平分線的交點(diǎn).2.6第1課時(shí)
1.略.2.35°,35°.3.50°,80°或65°,65°.4.C5.B 6.∠EBC=36°,∠C=∠BEC=72°.7.△ACD≌ABD(SSS),∠CAG=∠BAG.AG是等腰三角ABC的頂角平分線.∴AD垂直平分BC.8.99° 第2課時(shí)
1.略.2.△ABE,△ECD,△EBC.3.C4.△DBE是等腰三角形.因?yàn)椤螧=∠C=∠DEB.5.△AED是等腰三角,因?yàn)椤螮AD=∠BAD=∠ADE.6~7.略.第3課時(shí)
1.略.2.1,3.3.C4.△ADE是等邊三角形.因?yàn)槿齻€(gè)角都等于60°.5.略.6.任兩邊的垂直平分線的交點(diǎn)即為點(diǎn)O.7.BE=DC.因?yàn)椤鰽DC≌△ABE(SAS).第二章綜合練習(xí)1.GH,∠E,EO.1.B(4,-3);C(-4,3);6;8.3.24.45.64°;58°.6.D7.C8.A9.A10.(1)AB=AD,AE=AC,BC=DE,BF=DF,EF=CF;∠BAC=∠DAE,∠B=∠D,∠C=∠E,∠BAE=∠DAC,∠EAF=∠CAF,∠BFE=∠DFC,∠BAF=∠DAF.(2)△AEF與△ACF,△ABF與△ADF都關(guān)于直線MN成軸對(duì)稱.11.△ABC與△A′B′C′關(guān)于y軸對(duì)稱.12.△ACE≌△DCB(SAS).AE=BD.又∠HGE=∠CGB.∠HEG=∠CBG.∠HGE+∠HEG=∠CGB+∠CBG=90°.∠EHG=90°.AE⊥BD.13.4個(gè).①以BC為底邊的等腰三角形可作1個(gè);②以BC為腰的等腰三角形可作3個(gè).檢測(cè)站
1.60°2.AP;PC,AP;∠CAP.3.1;7.4.55°,55°或70°,40°.5.AC,∠C,△ABD.6.B7.B8.B9.D 10.A11.略.12.∠BAC=60°,∠C=90°,∠B=30°.13.∵△ABC≌△BAD.∠CAB=∠DBA,∴△EBA是等腰三角形.14.(1)5;(2)80°.15.∠ACD=180°-A2,∠BCE=180°-B2,∠ACB=90°.∴∠ACD+∠BCE=90°+∠DCE.∠DCE=45°.3.1第1課時(shí)
1.B≠0;B=0;A=0且B≠0.2.≠23.1,0.4.B5.D6.B7.x=-1且y≠08.19.ba-5;400.10.a=-1.11.略.12.n+13n-2 第2課時(shí) 1.略2.(1)2abc2;(2)xy(x+y);(3)a(a+b);(4)2x(x+y).3.A4.C5.B6.x≠1且x≠07.當(dāng)a≠0時(shí),a2a=12;當(dāng)m≠0,n≠0時(shí),n2mn=nm.8.M=-3x(a+x)2;x≠0,-a,a.9.5a2-1030a2-2a 3.2 1.略.2.2a(b-a)3.C4.C5.B6.(1)3y2x;(2)-1(x-y)2;(3)a+22-a;(4)2a2a-3b.7.-7 8.a-b+ca+b+c9.略.3.3 1~3.略.4.(1)-1ab;(2)ab18c;(3)4yx;(4)4yx.5.D6.C7.(1)a+1;(2)-b3x;(3)xy2;(4)aa+b8.-139.略.3.4 1.略.2.6a2b2,ab,3b,2a.3.(x+2)(x-2)24.D5.D6.2b24a2b2c2,3ac324a2b2c2;(2)5(a-b)215a(a+b)(a-b),3(a+b)215(a+b)(a-b);(3)3x-2y(3x+2y)(3x-2y),2(3x+2y)(3x-2y);(4)(x+1)2(x-1)(x+1)2,x(x-1)(x+1)(x-1)(x+1)2,x-1(x-1)(x+1)2.7.(m-n)2m-n,-mnm-n.8.cyz(b-c)(c-a)xyz(a-b)(b-c)(c-a),axz(a-b)(c-a)xyz(a-b)(b-c)(c-a),bxy(a-b)(b-c)xyz(a-b)(b-c)(c-a).9.(1)把前一個(gè)分式的分子,分母同乘-a2b即得下一個(gè)分式;(2)-a12b8a13b6.(3)(-1)na2n-2bn+1(-1)n+1a2n-1bn-1.3.5第1課時(shí)
1.略.2.(1)-b2a;(3)2aa-b.3.C4.D5.(1)y2x;(2)x+2;(3)3.6.(1)2+x;(2)3abb-a.7.x+2.8.原式=1.第2課時(shí)
1.略.2.b2-4c4a3.-4(x+2)(x-2)4.C5.D6.D 7.(1)3c3-4a2b12ab2c2;(2)6x2+xy+7y242x2y2;(3)2mn-m2n2-m2.8.-659.(1)11-a;(2)x2.10.1(x-1)(x-2),1(x-2)(x-3),1(x-3)(x-4),1x-100.第3課時(shí)
1.C2.D3.B4.(1)a-bb;(2)x+2.5.12 6.∵ca+b<1.∴c2(a+b)2<ca+b 3.6第1課時(shí)
1.(1)7x4y;(2)b2a;(3)2x-y;(4)a+ba-b2.ala+b,ala+b.3.23;49;13.4.A5.C6.(1)2;(2)2;(3)4.7.6 8.(1)xyx+y(天);(2)甲:myx+y(元),乙:mxx+y(元).9.(1)ba;(2)b-10a-10,b+10a+10;(3)b-10a-10<ba<b+10a+10.第2課時(shí)
1.略.2.8∶93.124.245.C6.D7.8a3 8.a-b=-39.260 mm10.5211.-5.第3課時(shí)
1.略.2.2∶33.33124.1 m5.10∶15∶216.D7.B8.x∶y∶z=(a+b)2∶(a2-b2)∶(a-b)29.34a,a,54a.10.6,8,10.11.63人,192人,45人.3.7第1課時(shí)
1.略.2.去分母,將分式方程轉(zhuǎn)化為整式方程求解,然后驗(yàn)根.3.-124.-325.B6.B7.D8.30x-2-30x=12.9.(1)x=4;(2)x=0.10.m=-187 11.(1)x=5;(2)a=6.第5個(gè)方程;(3)1+x2x=n+1x,x=2n+1.第2課時(shí)
1.略.2.無(wú)解3.C4.B5.不正確,錯(cuò)在第3步,沒(méi)有檢驗(yàn);方程無(wú)解.6.(1)x=3;(2)無(wú)解;(3)無(wú)解;(4)無(wú)解.7.a=-58.(1)①x=1;②x=2;③x=3;(2)方程1x-2-1x-3=1x-5-1x-6的解為x=4;方程1x+2-1x+1=1x-1-2x-2的解為x=0.第3課時(shí)
1.略.2.12010-x-12010=33.16+1x=13.4.D 5.(1)設(shè)去年每間屋的租金為x元,9.6x=10.2x+500;(2)8 000元.6.4 km/h7.37.5 km/h8.1.5 t 9.(1)設(shè)預(yù)定工期為x天,4x+xx+5=1,x=20(天).(2)采取聯(lián)合施工4天,然后由乙單獨(dú)施工的方案省工程費(fèi).第三章綜合練習(xí)
1.a≠32;x=-1.2.m=3,m≠1.3.24.12 5.a∶b=b∶c,c∶b=b∶a,ac=b26.127.3∶4∶58.39.C10.C11.A12.D13.B14.D15.616.a+b=0.17.(1)-5y2ax;(2)-x3y;(3)2xy;(4)3x+1;(5)1681x4y4;(6)2a2b2;(7)a-3a2-13;(8)-1a+1.18.(1)-715;(2)310.19.S1∶S2=1∶220.218 21.(1)無(wú)解;(2)x=1912;(3)x=-2;(4)無(wú)解.22.應(yīng)提高60 km/h23.(1)x≠-1,0,1;(2)原式=1.24.1次清洗.殘留農(nóng)藥比為11+y;分兩次清洗后,殘留農(nóng)藥比為:4(2+)2,11+y-4(2+y)2=y2(1+y)(2+y)2>0.第2種方案好.檢測(cè)站
1.x≠32,x=-23.2.x≠0且x≠-53.164.29 5.326.D7.C8.B9.B10.相等11.(1)mn-m;(2)ab;(3)2x-1x.12.11-x;-1.13.(1)x=4;(2)無(wú)解;(3)x=2.14.a=-115.14516.3617.28天 4.1第1課時(shí)
1~2.略.3.3.44.C5.B6.總產(chǎn)量1 757 t;平均產(chǎn)量8.53 t.7.9 000 m3 8.a·10%+b·15%+c·5%a+b+c(a,b,c為甲、乙、丙三種汽油原價(jià))第2課時(shí)
1.820,920,320.2.86 km/h3.C4.(1)甲;(2)乙.5.9.9%6.(1)1.84 kg;(2)3 312 kg.4.2 1.略.2.94.53.C4.x=225.平均數(shù):1 626,中位數(shù)1 680.6.26 cm7.9或108.(1)85.5;(2)41人;(3)高低分懸殊大.4.3第1課時(shí)
1.2;1與2.2.7與83.B4.平均數(shù)、中位數(shù)、眾數(shù)都是21歲5.平均數(shù)為2,中位數(shù)是3,眾數(shù)是1.6.(1)3個(gè);(2)32 000個(gè).7.(1)甲組:平均數(shù)80,中位數(shù)80,眾數(shù)90;乙組:平均數(shù)80.2,中位數(shù)80,眾數(shù)70;(2)略.第2課時(shí)
1.72.A3.平均數(shù)13千瓦時(shí),中位數(shù)22.5千瓦時(shí),眾數(shù)10千瓦時(shí).4.(1)眾數(shù)55 min,中位數(shù)55 min;(2)平均數(shù)為55 min.符合學(xué)校的要求.5.甲當(dāng)選 4.4 1~2.略.3.(1)平均直徑都是20 mm;(2)小明.4.乙地;甲地溫差比乙地大.5.(1)平均身高都是178 cm;(2)圖略.甲隊(duì)整齊.6.(1)x甲=1.69 m,x乙=1.68 m;(2)圖略.甲比較穩(wěn)定.4.5第1課時(shí) 1.1.22.10,26.3.10,1.8.4.A5.D6.S2甲=0.055,S2乙=0.105;果農(nóng)甲.7.(1)x=3,S2=2;(2)x=13,S2=2;(3)x=30,S2=200.8.(1)xA=0,S2A=2.29;(2)取-2,-1,0,3,0;xB=0,S2B=2.8.第2課時(shí)
1.乙2.D3.(1)略;(2)大剛的平均數(shù)為13.35,方差為0.004;小亮的平均數(shù)為13.3,方差為0.02.大剛成績(jī)好.4.(1)x蘋(píng)果=8,x香蕉=8,S2蘋(píng)果=9,S2香蕉=1.333;
(2)略;(3)9月份多進(jìn)蘋(píng)果.5.S2=1n[(x1-x)2+(x2-x)2+…+(xn-x)2]=1n[x21+x22+…+x2n-2x(x1+x2+…+xn)+nx2]=1n[x21+x22+…+x2n-2nx(x1+x2+…+xnn+nx2)]=1n[x21+x22+…+x2n-nx2].4.6 1.C2.略3.甲4.相差75.x甲=178,S2甲=0.6;x乙=178,S2乙=1.8.6.(1)x甲=200.8,S2甲=7.96;x乙=201.5,S2乙=38.05;(2)甲.第四章綜合練習(xí)
1.1.62 m2.8,8,8,1.23.20,18,184.4,3.5.b>a>c6.C7.D8.C9.(1)甲組:x甲=3.中位數(shù)2,眾數(shù)1,S2甲=7.67;乙組:x乙=3,中位數(shù)3,眾數(shù)3,S2乙=1.67;(2)乙組.10.(1)x=2 135.7(元),眾數(shù)為800元,中位數(shù)為1 600元;(2)略.11.(1)x=2,眾數(shù)為3,中位數(shù)為2;(2)68人.12.(1)22℃;(2)20.8℃;(3)146天.13.乙成績(jī)穩(wěn)定 檢測(cè)站
1.2.12元2.23.64.31.8℃,4.965.D6.C 7.D8.90.6分9.(1)x甲=5.6 cm,S2甲=1.84,x乙=5.6 cm,S2乙=1.04.(2)乙苗長(zhǎng)的比較整齊.10.(1)x甲=7,S2甲=0.4,x乙=7,S2乙=2.8;(2)甲.11.6 12.(1)甲班:平均分24,方差5.4;乙班中位數(shù)24,眾數(shù)21,方差19.8;(2)甲班42人,乙班36人;(3)甲班.綜合與實(shí)踐 略.5.1 1~2.略.3.面積相等的三角形,是全等三角形,假.4.D5.D6.B7~9.略.5.2 1.略.2.不正確.如正方形與菱形.3.小亮不對(duì);小瑩說(shuō)法正確.4.不正確.如2≠-2,但22=(-2)2.5.不正確;t=20t1+30t220+30.5.3 1~3.略.4.C5.直角定義;余角定義;對(duì)頂角相等;等量代換;余角定義.6.(1)C,E,F,G;(2)E;(3)K;(4)略.7.C 5.4 1.B2.C3.(1)∠D;內(nèi)錯(cuò)角相等,兩直線平行;(2)∠DEC;AB∥DE.同位角相等,兩直線平行.4.已知:∠CBE;兩直線平行,同位角相等;已知,∠CBE;等量代換;內(nèi)錯(cuò)角相等,兩直線平行.5.略.6.(1)如果兩個(gè)角相等,那么這兩個(gè)角是同角或等角的補(bǔ)角.真命題;(2)如果三角形中有兩個(gè)角是銳角,那么第三個(gè)角是鈍角,假命題,如∠A=80°,∠B=70°,∠C=30°.7.(1)延長(zhǎng)AE與CD相交于點(diǎn)G.∵AB∥EF.∴∠A+∠AEF=180°.∵AB∥CD,∴∠A+∠G=180°.∴∠A+∠AEF=∠A+∠G,∠AEF=∠G.∴EF∥CD;(2)360°.5.5第1課時(shí)
1.略.2.C3.D4.∠B=∠C,∠AOB=∠DOC.5.∠1>∠ACB>∠26.略.7.(1)∠A逐漸減小,∠B,∠C逐漸變大;若點(diǎn)A向下運(yùn)動(dòng),變化相反;(2)α=β+γ.5.5第2課時(shí)
1.(1)∠B=∠DAC;(2)∠A=∠D;∠CGE+∠B=180°.2.D3.B4.略.5.∠1=∠C+∠CDE,∠2=∠C+∠CED,∠1+∠2=180°.6.(1)∠EFD=90°-∠FED=12(∠A+∠B+∠C)-(∠B+12∠A)=12(∠C-∠B);(2)不變.5.6第1課時(shí)
1.D2.C3.(1)BC=EF或BE=CF;(2)∠A=∠D;(3)∠C=∠F.4.(1)△ABE≌△DCF(SAS),△ABF≌△DCE(SAS),△BEF≌△CFE;(2)略.5.△AFC≌△BED(ASA)6.取EF的中點(diǎn)M,連接GM,并延長(zhǎng)交FH于點(diǎn)N.GN分別交AD,BC于點(diǎn)P,Q.△PEM≌△QFM.沿GN將道路取直即可.第2課時(shí)
1.平行2.90°3.B4.D5.∵∠ABD=∠ADB,∴∠CBD=∠CDB.∴BC=DC.6.△ABD與△ACD都是等腰三角形,BD=AD=DC.7.△ABD≌△ACE(SAS).∠A=∠CAE=60°.∴△ADE為等邊三角形.8.∵△AEB≌△BDA(ASA).∴AE=BD,EB=DA,CE=CD,EF=DF.AF=BF.第3課時(shí)
1.=2.①②③3.A4.略.5.△ABD≌△AED(SAS),∴AB=AE.DC=AB+BD=AE+DE,DC=DE+EC,∴AE=EC.∴點(diǎn)E在線段AC的垂直平分線上.6.(1)∠A≠∠C.因?yàn)椤鰽BD與△CBD不全等;(2)∠A>∠C.因?yàn)锳B<BC,在BC上取BA′=BA.△ABD≌△A′BD.∠A=∠BA′D.∠BA′D>∠C,∴∠A>∠C;(3)當(dāng)AB=CB時(shí).∠A=∠C;當(dāng)AB<BC時(shí),∠A>∠C;當(dāng)AB>BC時(shí),∠A<∠C.第4課時(shí)
1.OA=OB.2.=.三角形的三內(nèi)角平分線相交于一點(diǎn).3.B4.B5.△ADE≌△ADF.AE=AD.△AEF為等腰三角形.6.△BEO≌△BFO(AAS),△BED≌△BFD(SAS).△EOD≌△FOD(SSS)或(SAS).7.DE=BD-CE.由DE∥BC.∠BOD=∠OBC=∠OBD.∴BD=OD.又∠OCE=∠OCF=∠BOC+∠OBC=∠BOC+∠BOE=∠COE.∴CE=OE.DE=OD-OE=BD-CE.第5課時(shí)
1.AB=AD或BC=DC(HL)2.D3.B4.作直線MN,過(guò)MN上一點(diǎn)D作MN的垂線l;在直線l上截取DA=h;以A為圓心,a為半徑畫(huà)弧交MN于點(diǎn)B,C兩點(diǎn);連接AB,AC.△ABC即為所求.5.連接AC.Rt△ABC≌RtADC(HL).∴BC=DC.Rt△BCE≌Rt△DCF(HL).6.連接AF,BF.△AEF≌△BEF△AFC≌△BFD(SAS).7.(1)Rt△OBD≌Rt△OCE(HL);(2)Rt△OBD≌△OCE(HL);(3)相等.第五章綜合練習(xí)
1.A2.C3.D4.B5.D6.略.7.120°8.∠2=∠1.∴∠2=∠C,AB∥CD.9.延長(zhǎng)EF交BC于點(diǎn)G.∵∠2=∠4,∴AB∥EF.∠3=∠B=∠EGC.∴DE∥BC.∴∠AED=∠ACB.10.∠ABE=∠FBD,∠ABE+∠AEB=90°,∠FBD+∠AFE=90°.∴∠AEB=∠AFE.∴AE=AF.11.△ACE≌△BDE(AAS),∴EC=ED.12.(1)∠D=∠AEC(同角的余角相等).△ACE≌△CBD.∴AE=CD;(2)BD=CE=12AC=6 cm.13.(1)Rt△ADE≌Rt△ADF;(2)DB=DC,Rt△DBE≌Rt△DCF(HL).14.(1)略;(2)連接BD.∠DBC=12∠B=30°.∵∠CDE=∠CED.∴∠CED=12∠ACB=30°.∴△DBE為等腰三角形.∵DM⊥BE,∴BM=EM.15.△BPD≌△BDC(SAS),△BCD≌△ACD(SSS).∠P=∠BCD=∠ACD=12∠ACB=30°.16.(1)作DF⊥AB,垂足為點(diǎn)E.AC=AE,DE=DC.∵∠B=∠A=45°,∴BE=DE.∴AB=AE+BE=AC+CD.(2)(1)中的等量關(guān)系仍成立.∵∠ACB>∠B,∴AB>AC.在AB上截取AG=AC.分別作DF⊥AC,DE⊥AB.△DCF≌△DGE.∵∠EGD=∠C=2∠B.∴∠B=∠BDG.BG=DG=DC.∴AB=AG+GB=AC+CD.檢測(cè)站
1.A2.C3.C4.三;△ODG≌△OEG,△DPG≌△EPG;△ODP≌△OEP,HL或AAS.5.略.6.FA=FD,∠ADF=∠DAF=∠DAC+∠CAF.∵∠DAC=∠BAD.∴∠B=∠ADF-∠BAD=∠DAF-∠DAC=∠CAF.7.(1)略;(2)∵CA=CE,∴∠CAE=∠E.∵∠ACB=∠CAE+∠E=2∠E,∠ACB=2∠BCD,∴∠E=∠BCD.CD∥AE.8.(1)①③或②③;(2)略.9.(1)△ABQ≌△PBC;(3)∠MBN=60°,△ABM≌△PBN(ASA).BM=BN.∴△BMN為等邊三角形.∠MNB=∠QBC.MN∥AC.總復(fù)習(xí)題
1.(3,4),等腰2.-53.50°,60°,70°.4.略.5.5,5.6.D7.C8.D9.B10.D11.(1)11-x;(2)x2-xy-2y23xy2;(3)-(1-m)2;(4)1-a.12.32°13.-314.設(shè)每天修x m,3 600x-3 6001.8x=20.x=80 m.15.(1)中位數(shù)12℃,眾數(shù)11℃;(2)1.143.16.分別作FG⊥BC,FM⊥AD,FN⊥AE,垂足分別為點(diǎn)G,M,N.FM=FG=FN.17.∵∠BAD=∠BDA,∴AB=DB=CD.∵BE=DE,∴△ABE≌△ADE.AB=AD,△ABD為等邊三角形.連接CF.△AEC≌△FEC.∵∠ACF=60°,∴△AFC為等邊三角形.∴AF=AC,AE=12AC.18.延長(zhǎng)BO交AC于點(diǎn)D.∠BOC=110°.19.作CF⊥AC,交AD延長(zhǎng)線于點(diǎn)F.∵∠BAC=90°,AD⊥BM.∴∠ABM=∠MAE.∵AB=AC,∴△ABM≌△CFA.∠1=∠F.AM=CF.∵AM=CM,∴CF=CM.∠FCD=45°=∠MCD.∴△FCD≌△MCD(SAS).∠2=∠F=∠1.總檢測(cè)站
1.a-12.(1)SSS;(2)SAS;(3)HL.3.5,5,5.25.4.4,3.5.△ABC≌△ABD,△ACE≌△ADE,△CEB≌△DEB.6.C7.D8.D9.D10.B11.113 850 kg 12.(1)x=-2;(2)無(wú)解.13.30 m14.∵△ABE≌△ACE,∴BE=CE,BD=CD.△BDE≌△CDE(SSS).15.(1)①②③④,①③②④,①④②③,②③①④,②④①③.(2)略.≤≥<>×≠÷′△∠°αβ⊥∥∵∴△≌△S△ACC′1.2.3.4.5.6.7.8.9.10.
第四篇:新目標(biāo)英語(yǔ)九年級(jí)unit7配套練習(xí)冊(cè)答案
Unit 7 WHere would you like to visit
Section A
I 1.educational 2.thrilling 3.to trek through the jungle 4.too stressed out 5.consider asking
II 1.thrillers;thrilling 2.to tour;touristy;tourists;tour 3.relaxing;relaxes;relaxed 4.tired;tiring 5.lively;lived;alive;liveliest
III.1.where there are;with 2.are supposed to 3.who can 4.is supposed to be 5.would like to
Section B
I.1.provide 2.easy 3.light 4.including 5.vacations
II.1.provide us with some useful information 2.In general;junk food 3.Traveling around;by taxi convenient to take;to most places 4.Unless you speak;yourself;it’s best;someone who can translate 5.which is best to travel by
6.give her some suggestions 7.is the most expensive;is 8.get a room with a kitchen
III.1~6 ADBABC
IV.1~5 DFCBE
Self Cheak and Reading
I.1.in which thousands of;take part in 2.find out;answers to;as soon as possible 3.According to;the most popular choice of job 4.continue singing;so that;provide better lives for 5.It seems;work as
6.Quite a few;are willing to
7.hold on to;come true 8.On the one hand;on the other hand 9.volunteer translators;translated;for
II.1.as soon as they can 2.provie;with 3.less realistic than 4.were ready to 5.in order that
III.1~5 CDBAC 6~10 CADDB
第五篇:新目標(biāo)九年級(jí)英語(yǔ)unit 8配套練習(xí)冊(cè)答案
Unit8 l'll help clean up the city parks.Secion
A
I.II.III.1.makes;happier 2.establish;learn 3.thinks up 4.to do 5.Do you
IV.1~6 DCCACB
Section
B I.II.1.ran out of 2.takes after 3.put up 4.call up 5 give out 6 trying to
III.1.takes after 2.spent on spent buying 3.similar to 4.repair 5.What did
IV.1~6 BAAABC 1.deaf 2.fix 3.pleasure 4.shut 5.fetch 1.homeless 2.hunger 3.established 4.coach 5.sign 1.set up 2.think up 3.cheer;up 4.clean up 5.put off 6.put up V.1~5 FGADC 6~7 EB
Self Check and Reading
I.1.fetch 2.pleasure 3.blind 4.imagine 5.specially 6.filled 7.carried 8.deaf 9.shut ting 10.worked out
II.1.homeless 2.later 3.easiest 4.hunger 5.pleasure 6.holding 7.clean 8.cheered 9.to set 10.interviewer
III.1~5 ACBBA 6~10 ACAAB 11-14CBAD
IV.1.old enough to 2.How many does have 3.run out of 4.spends on 5.takes after 6 were playing 7 Would have 8 How do Ⅴ BDACC BACAB Ⅵ 略