第一篇：2015年高一英語(yǔ)暑假作業(yè)答案(新人教版)

2015年高一英語(yǔ)暑假作業(yè)答案（新人教版）

第二部分 閱讀理解(共兩節(jié)，滿分分)(共小題;每小題分，滿分分)閱讀下列短文，從每題所給的四個(gè)選項(xiàng)(A、B、C、和D)中，選出最佳選項(xiàng)，并在答題卡上將該項(xiàng)涂黑。

I was telling my boy Sonny the story of the hare and the tortoise.At the end I said, “ Son, remember: Be slow and steady, and that will win the race.Dont you think theres something to learn from the tortoise”

Sonny opened his eyes wide, “Do you mean next time when Im entering for the 60-metre race I should wish that Billy, Tony and Sandy would all fall asleep halfway”

I was shocked, “But the tortoise didnt wish that the hare would fall asleep!”

“He must have wished that,” Sonny said, “Otherwise how could he be so foolish as to race with the hareHe knew very well the hare ran a hundred times faster than he himself did.”

“He didnt have such a wish,” I insisted.“He won the race by perseverance, by pushing on steadily.” Sonny thought a while.“Thats a lie,” he said.“He won it because he was lucky.If the hare hadnt happened to fall asleep, the tortoise would never have won the race.He could be as steady as you like, or a hundred times steadier, but hed never have won the race.Thats for sure.”

I gave up.Todays children are not like what we used to be.Theyre just hopeless.1.The writer argued with his son because ______________.A.he liked tortoises while his son liked hares B.they disagreed about whether the tortoise was foolish C.he tried to teach his son a moral lesson but the son had totally different opinion D.he liked the story of the hare and the tortoise while his son didnt.2.Sonny believed that the tortoise ______________.A.won the race by his own hard working B.took a risk by agreeing to run a race C.was not given a fair chance in the race D.in fact did win the race luckily 3.Billy, Tony and Sandy must be_______________.A.boys who were unknown to Sonnys father B.boys who Sonny has run races with before C.boys who Sonny has never raced with before D.boys who Sonny did not expect to race with again 4.The writer thinks that his generation______________.A.are cleverer than Sonnys generation B.have the same ideas about life as Sonnys generation C.are more hopeful than Sonnys generation D.have different ideas about life from Sonnys generation 第二節(jié)(共5小題，每小題2分，滿分10分)根據(jù)短文內(nèi)容，從短文后的選項(xiàng)中選出能填入空白處的最佳選項(xiàng)，選項(xiàng)中有兩項(xiàng)為多余選項(xiàng)。

Do you know AustraliaAustralia is the largest island in the world.It is a little smaller than China.It is in the south of the earth.1The population of Australia is nearly as large as that of Shanghai.2The cities in Australia have got little air or water pollution.The sky is blue and the water is clean.You can clearly see fish swimming in the rivers.Plants grow very well.Last month we visited Perth, the biggest city in western Australia, and went to a wild flowers exhibition.3We had a wonderful time.Perth is famous for its beautiful wild flowers.In spring every year Perth has the wild flowers exhibition.After visiting Perth, we spent the day in the countryside.We sat down and had a rest near a path at the foot of a hill.It was quiet and we enjoyed ourselves.Suddenly we heard bells ringing at the top of the hill.4There were about three hundred sheep coming towards us down the path.5After a short drive from any town, you will find yourself in the middle of white sheep.Sheep, sheep, everywhere are sheep.A.The government has made enough laws to fight pollution.B.Australia is the sixth largest country in the world.本文由為您提供供廣大考生參考學(xué)習(xí)，希望對(duì)大家有所幫助，高中頻道推薦。

第二篇：高一 英語(yǔ)暑假作業(yè)

Assignments for the Summer Vacation（假期作業(yè)）

2011-7

Listening（聽(tīng)力）:

? Studio Classroom（空中英語(yǔ)教室）每天30分鐘

? Movies（電影）（帶英文字幕）

Speaking（口語(yǔ)）:

? Selected English Articles for Reading(朗讀文章并錄音)

? Studio Classroom（空中英語(yǔ)教室）

? Texts from our textbooks（課本中的課文）

Reading（閱讀）:

? Studio Classroom（空中英語(yǔ)教室）

? 21st Century（21世紀(jì)英文報(bào)）

? Novels（小說(shuō)）

Writing（寫(xiě)作）:

?5 essays（5篇作文），包括:book reports（兩篇讀書(shū)報(bào)告）film reviews（兩篇觀影心得）

A diary or free writing（一篇日記或隨筆）

? Word bank: 2 words/ expressionsa day(25days)（單詞積累；每日兩詞/詞組，共25

天）

? Handwriting（書(shū)法練習(xí)）

The works to be handed in（需上交的作業(yè)）

? The Recording of your reading（文章錄音）

? 5 essays(5篇作文)

? Word bank(單詞積累)

? Handwriting（書(shū)法練習(xí)）

? Writing portfolio.注意： 以上作業(yè)將計(jì)入下學(xué)期平時(shí)成績(jī)。

開(kāi)學(xué)考試內(nèi)容：《空中英語(yǔ)》（50%）、及課本詞匯（30%）、語(yǔ)法（20%）。

第三篇：高一英語(yǔ)暑假作業(yè)

高一英語(yǔ)暑假作業(yè)

一． 必做題

1.必修四單元形成性測(cè)試卷（六套）

2.《雙語(yǔ)報(bào)》47期---51期（綜合復(fù)習(xí)版、快樂(lè)閱讀版）

3.自學(xué)預(yù)習(xí)必修五Moduole1（見(jiàn)提綱）

二． 選做題

1.甲+班：21st Century 暑假合刊、《快樂(lè)閱讀》

2.甲班：21st Century 暑假合刊（初三版）、《快樂(lè)閱讀》

第四篇：2015年高一英語(yǔ)暑假作業(yè)答案(合訂本)

2015年高一英語(yǔ)暑假作業(yè)答案（合訂本）

從A、B、C、D四個(gè)選項(xiàng)中，選出可以填入空白處的最佳選項(xiàng)。

1.I could _______ by the way she walked that her knee was still bothering her.A.separate B.tell C.find D.divide 2.______ in a well-known university is what everybody wishes for.A.Educated B.Being educated C.To educate D.Educating 3.His classmates offered him their congratulations ______ his successful performance.A.at B.on C.for D.of 4._______every member has arrived, lets set about _____ the plan for the next five years.A.Since;to work out B.Because;work out C.Now that;working out D.For;work out 5.Here are the first three books of his poem works, with the fourth one to _____ next month.A.come out B.publish C.replace D.work out 6.As he works in a remote area, he visits his parents only _______.A.anxiously B.occasionally C.urgently D.hopefully 7.His English is improving _______, which makes both his parents and his teacher happy.A.now and then B.little by little C.sooner or later D.one after another 8.It is surprising that such a young boy can swim ______ the river ______ 100 meters wide.A.over;measured B.across;measuring C.across;measures D.through;measuring 9.Li Ming is a student who is easy _____ though he has some trouble _____ his lessons.A.to be got along with;in B.to get along with;with C.to get along;in D.getting along with;with 10.I thought he would offer to pick me up._______, he even refused me when I asked him to do so.A.In other words B.Otherwise C.Whats more D.However 11.It suddenly ________ me how we could improve the situation.A.got B.struck C.beat D.occurred 12.Seeing the ______ sight, the girl was nearly _______ to death.A.terrifying;terrifying B.terrified;terrified C.terrifying;terrified D.terrified;terrifying 13._____ in a heavy snow, he didnt get there in time.A.Catching B.Catch C.Caught D.To catch 14.Dont blame yourself too much.Everyone has his ______ and weaknesses.A.powers B.strengths C.forces D.energies 15.The reason _____ he was late for the meeting was ____ he was held up by traffic jam during rush hours.A.why;because B.that;that C.why;that D.that;because 16.The child ______ in the countryside knows how to _____ animals like dogs, pigs and so on.A.raised;bring up B.brought up;raise C.fed;raise D.fed up;bring up 17.Scientists said that the winter of 2011 was _____ cold, and in fact it was much colder than predicted.A.frozen B.freezing C.freezingly D.froze 18.A local woman didnt _______ her tears when she saw her store destroyed by the fire.A.hold out B.hold back C.hold up D.hold on 19.The fact that she was foreign made ______ difficult for her to get a job in that country.A.this B.that C.her D.it 本文由為您提供供廣大考生參考學(xué)習(xí)，希望對(duì)大家有所幫助，高中頻道推薦。

第五篇：2018高一數(shù)學(xué)暑假作業(yè)答案（推薦）

2018高一數(shù)學(xué)暑假作業(yè)答案

：學(xué)習(xí)應(yīng)該是一件輕松的活動(dòng)。學(xué)習(xí)其實(shí)不用刻意去學(xué)習(xí)，它靠的是日積月累和逐漸的積淀。小編為大家分享高一數(shù)學(xué)暑假作業(yè)答案，希望能幫助同學(xué)們復(fù)習(xí)本門(mén)課程!

暑假作業(yè)(一)

一.選擇題: D C A

二.填空題: 4.5.6.4.解: ,又，且a、b、c成等比數(shù)列，由余弦定理，得。，即。

5.解：。6.解: 由正弦定理及，得，即。，而。

。又，得。，即(當(dāng)且僅當(dāng)時(shí)=成立)。，即ABC的面積的最大值為。故填。

三.解答題:

7.解:(Ⅰ)由，得，由，得.所以.(Ⅱ)由正弦定理得.所以的面積

.8.解:(Ⅰ)由余弦定理及已知條件得，又因?yàn)榈拿娣e等于，所以，得.聯(lián)立方程組解得，.(Ⅱ)由題意得，即，當(dāng)時(shí)，，，當(dāng)時(shí)，得，由正弦定理得，聯(lián)立方程組解得，.所以的面積.9.解:∵sinA+cosA=cos(A-45)=，cos(A-45)=。又0

A=105.tanA=tan(45+60)=.SinA=sin105=sin(45+60)

=sin45cos60+cos45sin60=.S△ABC=ACAbsinA=23=。

解法二：∵sinA+cosA= ①,(sinA+cosA)2=.2sinAcosA=-.∵0

①-②，得cosA=。tanA=。(以下同解法一)

10.解:(1)依題意，,由正弦定理及

(2)由 由(舍去負(fù)值)

從而 由余弦定理，得

代入數(shù)值，得解得：

暑假作業(yè)(二)

一.選擇題: B D B

3.解:在△ABC中，∵a, b, c成等差數(shù)列，2b=a+c.又由于B=30，S△ABC=acsinB

=acsin30=.ac=6.b2=a2+c2-2accosB=(a+c)2-2ac-2accosB=4b2-26-26cos30.解得b2=4+2=(1+)2.∵b為三角形的邊，b0.b=1+.應(yīng)選B.二.填空題: 4.5.6.4.解: ,。

5.解：由題意得:，兩式相減，得.由的面積，得，所以.6.解:由得9+24sin(A+B)+16=37，又

當(dāng)時(shí)，不等于6，故否定，.三.解答題:

7.解: 在△ABP中，APB=30BAP=120,由正弦定理知得.在△BPC中，又PBC=90，可得P、C間距離為(海里)

8.解:(1)由余弦定理，(Ⅱ)由，且得由正弦定理，解得。所以。由倍角公式，且，故.9.解:(Ⅰ)由，且，，又，.(Ⅱ)∵,，又

.10.解:(Ⅰ)由題設(shè)及正弦定理，有。故。因?yàn)殁g角，所以。由，可得，得。

(Ⅱ)由余弦定理及條件，有，故。由于△面積，又，當(dāng)時(shí)，兩個(gè)不等式中等號(hào)同時(shí)成立，所以△面積的最大值為。暑假作業(yè)(三)

一.選擇題: A D D

3.解：不妨設(shè)ab，則，另一方面，a為最長(zhǎng)邊，b為最短邊。設(shè)其夾角為，則由余弦定理可得a2-ab+b2=a2+b2-2abcos，解得cos=，又∵為三角形的內(nèi)角，=60。故選D。

二.填空題: 4.5.6.6.解:因?yàn)殇J角△ABC中，A+B+C=，所以cosA=，則，則bc=3。將a=2，cosA=，c=代入余弦定理：中得,解得b=

三.解答題:

7.解:(Ⅰ)由題設(shè)及正弦定理，有.故.因?yàn)闉殁g角，所以.由，可得，得，.(Ⅱ)由余弦定理及條件，有，因，所以.故，當(dāng)時(shí)，等號(hào)成立.從而，的最大值為.8.證：(1)∵sin(A+B)= , sin(A-B)=...tanA=2tanB.(2)∵

設(shè)AB邊上的高為CD，則AB=AD+DB=，由AB=3，得CD=2+，AB邊上的高等于2+。

9.解: ∵，或，(1)時(shí)，;

(2)時(shí)。

10.解: ∵A、B、C為△ABC的三內(nèi)角，,.令,∵A是△ABC的內(nèi)角 ,當(dāng)時(shí)，為其最大值。此時(shí)

暑假作業(yè)(四)

一.選擇題: D D A

1.解:由得即，又在△中所以B為或.二.填空題: 4.5.6.4.解:由題意，得為銳角，，由正弦定理得 ,.5.解: ,又, 解得.，是銳角..,，.又，.,.6.解：由余弦定理，由，且得由正弦定理，解得

。所以。由倍角公式，且，故.三.解答題:

7.解:(1)由,得，則有 =,得 即.(2)由,推出而,即得，則有 ,解得.8.解:(Ⅰ)由及正弦定理得，,，是銳角三角形,.(Ⅱ)由面積公式得 由余弦定理得21世紀(jì)教

由②變形得.解法二：前同解法1，聯(lián)立①、②得,消去b并整理得

解得.所以,故.21世紀(jì)教育網(wǎng)

9.解: 由，,，又，由得, 即，,，由正弦定理得.10.解:()∵,=,且,，即,∵，.由的面積，得

由余弦定理得，又,，即有=4.()由()得，則12=, ,∵,，故的取值范圍為.方法二：由正弦定理得,又()得.==,∵，, ,的取值范圍為.暑假作業(yè)(五)

一.選擇題: C C A

二.填空題: 4.或 5.63 6.三.解答題:

7.解:設(shè)數(shù)列{an｝的公差為d，首項(xiàng)為a1，由已知得 5a1 + 10d =-5, 10a1 + 45d = 15，解得a1=-3，d=1。Sn = n(-3)+，∵{｝是等差數(shù)列且首項(xiàng)為=-

3、公差為。

Tn = n(-3)+

8.解:(1)由已知，得.當(dāng)2時(shí)，,所以,由已知，,設(shè)等比數(shù)列的公比為，由得，所以,所以.(2)設(shè)數(shù)列的前項(xiàng)和為，則，兩式相減得,所以.9.解：(I)由條件又是公差為1的等差數(shù)列，=n2(nN*)。

解法二：由即，又

∵是公差為1的等差數(shù)列，即，(II)=(1)n，=12+2232++(1)nn2。

① n是偶數(shù)時(shí)，=(2212)+(4232)++[n2(n1)2]=;

② n是奇數(shù)時(shí)。

10.解：(Ⅰ)當(dāng)時(shí)，即是等比數(shù)列.(Ⅱ)由(Ⅰ)知，若為等比數(shù)列，則有而故，解得，再將代入得成立，所以.暑假作業(yè)(六)

一.選擇題: D D D

1.解：設(shè)等比數(shù)列的公比為，則有。當(dāng)時(shí)，(當(dāng)且僅當(dāng)q=1時(shí)取等號(hào));當(dāng)時(shí)，(當(dāng)且僅當(dāng)q=-1時(shí)取等號(hào))。所以的取值范圍是，故選D。

3.解：∵每4個(gè)括號(hào)有10個(gè)數(shù)，第104括號(hào)中有4個(gè)數(shù)，第1個(gè)為515，和為

515+517+519+521=2072，選D。

二.填空題: 4.5.6.3

4.解：。，將代入成立。

5.解：。

6.解：3 由，可得。

。故填3。

三.解答題:

7.解:(1)an=;(2)an=(-1)n.(3)an=;(4)

(5);(6)an=n+

8.解：∵{an}是等差數(shù)列，a2+a4=2a3 ,∵a2+a4=b3,b3=2a3,∵{bn}是等比數(shù)列，b2b4=b23 ，∵b2b4=a3 , a3=b23 ,即b3=2b23, ∵b30，b3=,a3=,由a1=1，a3=,公差., 由.當(dāng);當(dāng).9.解:(Ⅰ)由 得 3anan+1 +an+1 = an ,從而，即,數(shù)列是以為首項(xiàng)3為公差的等差數(shù)列。

(Ⅱ)設(shè)bn = anan+1 ,則 ,，.10.解：(1)由題意，為等差數(shù)列，設(shè)公差為，由題意得，.(2)若，時(shí)。

故。

暑假作業(yè)(七)

一.選擇題: B C B

1.解：，當(dāng)時(shí)，有;當(dāng)，有。綜上，有，選B。

3.解：易知，且。當(dāng)時(shí)，在時(shí)0，故選B。二.填空題: 4.14 5.6.;;

三.解答題:

7.解：(1)設(shè)數(shù)列共2m+1(mN*)把該數(shù)列記為{an｝，依題意a1+a3++a2m+1=44且

a2+a4++a2m=33，即(a2+a2m)=33.(1)(a1+a2m)=44.(2)(1)(2)得.m = 3.代入(1)得a2+a2m = 22，am+1==11 即該數(shù)列有7項(xiàng)，中間項(xiàng)為11

方法二: S奇+S偶=Sn;S奇─S偶=a中;Sn=na中 a中=11

(2)(奇數(shù)項(xiàng)之和)，兩式相除得到：(m+1)/(m─1)=4/3 m=7，再聯(lián)立方程組解得：a1=20,am=2d=─3an=─3n+23

8.解：(Ⅰ)∵a3，a5是方程的兩根，且數(shù)列的公差d0，a3=5，a5=9，公差 又當(dāng)n=1時(shí)，有b1=S1=1-

當(dāng)數(shù)列{bn}是等比數(shù)列，(Ⅱ)由(Ⅰ)知

9.解：(Ⅰ)由,得，兩式相減得，即，又,，, ，數(shù)列是首項(xiàng)為，公比為的等比數(shù)列 ,.(Ⅱ)由(Ⅰ)知,.(Ⅱ)方法二: 由已知 ① 設(shè)，整理得 ②, 由①、②，得.即①等價(jià)于,數(shù)列是等比數(shù)列，首項(xiàng)

為，公比為，.10.解：(1)∵.又.是一個(gè)以2為首項(xiàng)，8為公比的等比數(shù)列,.(2),.最小正整數(shù).暑假作業(yè)(八)

一.選擇題: D B A

二.填空題: 4.-4 5.6.5.解：依題意，而，故，根據(jù)等比數(shù)列性質(zhì)

知也成等比數(shù)列，且公比為，即，.6.解：，。

三.解答題:

7.解：(1)設(shè){an}的公差為d, {bn}的公比為q，則,解得(舍)或.an=1+(n-1)(-2)=3-2n, bn=(-1)n-1.(2)設(shè)Sn=a1b1+a2b2+a3b3++anbn,則Sn=a1-a2+a3-a4++(-1)n-1an，當(dāng)n為偶數(shù)時(shí)Sn=(-d)=n;當(dāng)n為奇數(shù)時(shí)，Sn=Sn-1+(-1)n-1an=(n-1)+an=2-n.方法二：Sn=a1b1+a2b2+a3b3++anbn,，.將q=-1, bk=(-1)k-1, ak=3-2k,(k=1, 2,，n), d=-2，代入整理可得：Sn=1+(n-1)(-1)n.8.解：(1)由題意知：4(an+1-an)(an-1)+(an-1)2=0,(an-1)(4an+1-3an-1)=0.∵a1=2,an-10，即4an+1=3an+1.假設(shè)存在常數(shù)C，使{an+C}為等比數(shù)列，則：為常數(shù).c=-1，故存在常數(shù)c=-1，使{an-1}為等比數(shù)列.(2), 從而,.9.解：(Ⅰ)當(dāng)時(shí)，當(dāng)時(shí)，.又滿足,.∵，數(shù)列是以5為首項(xiàng)，為公差的等差數(shù)列.(Ⅱ)由已知，∵，又，數(shù)列是以為首項(xiàng)，為公比的等比數(shù)列.數(shù)列前項(xiàng)和為.10.解：(Ⅰ)

(Ⅱ)∵

猜想：是公比為的等比數(shù)列.證明如下：

∵，是首項(xiàng)為的等比數(shù)列.暑假作業(yè)(九)

一.選擇題: A C D

二.填空題: 4.7 5.6.1

4.解：據(jù)題意，有，故前7項(xiàng)為正數(shù)。

5.解：。

三.解答題:

7.解：(1)由已知有，解得，所以。

當(dāng)時(shí)，(2)令，則，當(dāng)時(shí)。。

8.解：設(shè)等差數(shù)列的公差為，前n項(xiàng)和為，則，是等差數(shù)列。

解法二：設(shè)的前n項(xiàng)和為，是等差數(shù)列。

9.解：(I)設(shè)等差數(shù)列的公差為d.由即d=1.所以即

(II)∵，10.解：(Ⅰ)由 得

即

∵，解得，(Ⅱ)∵是首項(xiàng)、公比的等比數(shù)列，故則數(shù)列的前

前兩式相減，得，即

暑假作業(yè)(十)

一.選擇題: C A B

二.填空題: 4.5.6.三.解答題:

n項(xiàng)和

7.解：(Ⅰ)由題設(shè)

(Ⅱ)若當(dāng) 故

若當(dāng)

故對(duì)于

8.解：(1)設(shè)是公差為d，的公比為q，則依題意有q0且

解之得。

(2)∵，,① ,② ②-①得:.9.解：(1)斜率為1，縱截距為2的直線方程為： 即是以2為公差，2為首項(xiàng)的等差數(shù)列，(2)，于是，即為遞增數(shù)列，的最小項(xiàng)為

10.解：(1)設(shè)第一年的森林的木材存量為，第年后的森林的木材存量為，則，，.(2)當(dāng)時(shí)，有得即，.即經(jīng)過(guò)8年后該地區(qū)就開(kāi)始水土流失.暑假作業(yè)(十一)

一.選擇題: A C C

二.填空題: 4.512 5.24 6.三.解答題:

7.解：設(shè)這四個(gè)數(shù)為：，則，解得：或，所以所求的四個(gè)數(shù)為：;或.8.解：(1)當(dāng)n=1時(shí)，當(dāng)，是以2為公比，4為首項(xiàng)的等比數(shù)列。

(2)，是以1為首項(xiàng)，1為公差的等差數(shù)列。

(3)，兩式相減得：。，即的前n項(xiàng)和為：。

9.解：(1)由整理得.又，所以是首項(xiàng)為，公比為的等比數(shù)列，得

(2)由(1)可知，故.則

又由(1)知且，故，因此為正整數(shù).10.解：(Ⅰ)=3，=6.由0，0，得03，又，=1，或=2.當(dāng)=1，02時(shí)，共有2個(gè)格點(diǎn);當(dāng)=2，0時(shí)，共有個(gè)格點(diǎn).故.(Ⅱ)由(1)知=，則-=.當(dāng)3時(shí)，.又=9==，所以，故.總結(jié)：以上就是高一數(shù)學(xué)暑假作業(yè)答案的全部?jī)?nèi)容，希望同學(xué)們?cè)谧鲱}的過(guò)程中養(yǎng)成不斷總結(jié)的好習(xí)慣，考試中避免出現(xiàn)技術(shù)性錯(cuò)誤，在高中取得最好的成績(jī)!