第一篇:2014年葫蘆島市普通高中教學(xué)質(zhì)量監(jiān)測(cè)高一英語答案及評(píng)分標(biāo)準(zhǔn)
葫蘆島市普通高中2013--2014學(xué)年教學(xué)質(zhì)量檢測(cè)
高一英語答案
聽力1—5 CCABB6—10 BABAA11—15 ABBAC16—20 CBCAB
閱讀21—24 CADA25—28 DBBC29—31 CDC32—35 BBAC36—40 CBAFE 完形填空41—45 CDABC46— 50 BDADC51—55 DACAC56—60 BDACB
語法填空61.to rent62.or63.suitable64.within65.None66.have been67.what
68.reasonable69.expensive/dear70.another
短文改錯(cuò)
Dear Sir,a∧see the doctor.tiredtotakeseriousmedicinefordrinkwillis
you for help?
Yours,Mike
書面表達(dá)
One possible version:
Dear Li,I am very glad to be a guest of your family.Thank you for accepting me.As an exchange student, I am eager to know more about China, especially Chinese culture.And I think the best way to achieve the purpose is to stay with your family and communicate with you.That’s why I choose homestay.What’s more, I love Chinese dishes, which plays an important part in Chinese culture.Also, homestay will give me more chances to make Chinese friends.I will be in your home next month.Can you prepare me a separate room? And Can I have breakfast and supper with your family members from Monday to Friday?
Looking forward to your reply.Best wishes!
Yours,Jim
第二篇:2014.7葫蘆島市普通高中教學(xué)質(zhì)量監(jiān)測(cè)高一地理答案及評(píng)分標(biāo)準(zhǔn)
2014年葫蘆島市普通高中教學(xué)質(zhì)量監(jiān)測(cè)高一地理答案及評(píng)分標(biāo)準(zhǔn)
1-5 BCABD 6-10 ABCAC 11-15 DDCCB 16-20 CBADB 21-25 CADAC
26.(10分)
(1)環(huán)境質(zhì)量下降;交通擁堵;居住條件差;就業(yè)壓力大。(4分)
(2)城市化速度快,城市規(guī)模過大,與經(jīng)濟(jì)發(fā)展不協(xié)調(diào)。(3分)
(3)環(huán)境方面:經(jīng)濟(jì)發(fā)展以清潔生產(chǎn)為主;合理布局有污染的企業(yè)。交通方面:大力發(fā)展公共交通;增加立交橋等交通設(shè)施。能源利用方面:使用清潔能源、可再生能源;提高能源利用率,節(jié)能減排。(環(huán)境、交通、能源各答出一條即可,每條1分,共3分)
27.(12分)
(1)地形、河流。(4分)(2)完善交通運(yùn)輸網(wǎng);縮短運(yùn)輸距離和時(shí)間;加強(qiáng)區(qū)際聯(lián)系;帶動(dòng)沿線地區(qū)經(jīng)濟(jì)發(fā)展。(8分)
28.(12分)
(1)工業(yè)主要分布在東部;農(nóng)業(yè)主要分布在西部(2分)(2)政策支持;勞動(dòng)力充足;臨近香港;交通便利。(4分)(3)便于企業(yè)間交流與協(xié)作;降低生產(chǎn)成本;獲得規(guī)模效益。(6分)
29.(16分)
(1)有利:夏季高溫多雨(雨熱同期);(2分)位于平原地區(qū),地勢(shì)平坦;(1分)臨近河流,有灌溉水源(或土壤肥沃)。(1分)不利:降水變率大,多旱澇災(zāi)害;(2分)冬季氣溫低,受寒潮影響。(2分)
(2)交通改善;保鮮技術(shù)提高;政策支持;溫室、大棚等農(nóng)業(yè)生產(chǎn)技術(shù)改進(jìn);市場(chǎng)需求量增大等。(每點(diǎn)1分,共5分)
(3)改善生態(tài)環(huán)境;減輕自然災(zāi)害;增加經(jīng)濟(jì)收入。(3分)
第三篇:2016九年級(jí)教學(xué)質(zhì)量檢測(cè)英語答案及評(píng)分標(biāo)準(zhǔn)
九年級(jí)教學(xué)質(zhì)量檢測(cè)英語試卷
參考答案及評(píng)分標(biāo)準(zhǔn)
選擇題(70分)
I.1-5 BACAC
6-10 BCBAB II.14-18 CBACB
19-23 CBCAB
24-28 ACBAC III.29-33 CABCB 34-38 CABCA
IV.39-42 DDAB
43-46 DBCB
47-50ABAC
51-54BDBC
55-58 D C A B 評(píng)分標(biāo)準(zhǔn):1-
10、14-28小題,每小題1分,錯(cuò)誤不給分。29-58小題,每小題1.5分,錯(cuò)誤不給分。
非選擇題(30分)聽說部分:
11.Anna is a happy girl.She has a large family.She has four brothers and sisters.At school she likes her teachers and they like her, too.Her favourite class is history and she often reads books about history.Her best friend is Betty.They do many things together, such as swimming, playing basketball and riding bikes.She also has many other friends.They often go to the mall, go to the movies and go to restaurants on weekends.評(píng)分標(biāo)準(zhǔn):正確復(fù)述的日常生活,包括五個(gè)要點(diǎn),3分;還正確地補(bǔ)充了其他聽力信息3分。其他情況酌情扣分。
12.Which grade are you in?
13.How many classes do you have every day? 該題答案只要合理可以給滿分;出現(xiàn)拼寫錯(cuò)誤不扣分,語法錯(cuò)誤三個(gè)或以上扣1分。
評(píng)分標(biāo)準(zhǔn):正確表達(dá)意思,每小題1分;有1-2個(gè)語法、拼寫錯(cuò)誤,扣0.5分,完全錯(cuò)誤不給分。
筆試部分:
V.59.who/that 60.smiling
61.to fix 62.for
63.friendly
64.months
65.Though/Although 66.filled
67.were
68.so 評(píng)分標(biāo)準(zhǔn):每小題1分,錯(cuò)誤不給分。
VI、書面表達(dá)(15分)
Refuse to be Phubbers
With the development of the Internet, smart-phones are widely used by people.Phubbers can be seen everywhere.While eating with family or friends, some people are always busy playing with their smart phones.It has bad effects on the relationship with their relatives and friends.Even worse, when some people cross the street, drive a car or work, they still concentrate on their mobile phones, which can easily cause traffic accidents.It’s very dangerous.Other teenagers stay up playing games.I think it does great harm to their health as well as study and work.In my opinion, we’d better make good use of smartphones.Don't focus on them too much.I do believe that face-to-face conversations will bring us more pleasure than chatting online.Let's raise our heads and refuse to be phubbers from now on!
該作文題采用整體印象評(píng)分法。
第一檔次13-15分:條理清楚,意思連貫,語句通順,標(biāo)點(diǎn)正確。
第二檔次10-12分:條理較清楚,意思連貫,語句通順,標(biāo)點(diǎn)及語法有少數(shù)錯(cuò)誤。第三檔次 7-9分:條理不甚清晰,語句還連貫,語法標(biāo)點(diǎn)有一些錯(cuò)誤。
第四檔次 4-6分:語句凌亂,條理不很清晰,能明白作者大致的意思,語言不規(guī)范,較多語法錯(cuò)誤。第五檔次 3分或3分以下:語句凌亂,條理很不清晰,不能明白作者大致的意思,語言不規(guī)范,語法錯(cuò)誤多。
第四篇:葫蘆島市普通高中2012-2013學(xué)年第一學(xué)期期末高一英語答案doc
葫蘆島市普通高中2012--2013學(xué)年上學(xué)期期末考試
高一答案
一、聽力
1—5 CCABB6—10 BABAA11—15 ABBAC16—20 CBCAB
二、單項(xiàng)填空
21—25 BABCB26—30 BDDCB31—35 DCABA
三、完形填空
36—40 BCDBA41—45 DBCAD46—50 BCBAD51—55 CABDA
四、閱讀理解
56—59 ABCA60—63 BDAC64—67 CBAA68—70 DAB71—75 CBEGF
五、短文改錯(cuò)
which
to
∧beforethat he forgot to get off at his station.He didn’t know ituntil
waitedlatewasmuch important than football!”
六、書面表達(dá)
Pollution Harms Us
Our school lies at the foot of a mountain with a river passing by.There used to be many green trees and all kinds of flowers in our school all the year round.It looked like a beautiful garden and was a nice place for us to study in, but everything has changed since a chemical works was built near our school a year ago.Every day it produces a lot of waste water and harmful gases.The terrible pollution has done great harm to our health and the great noise from the factory has greatly affected our teaching and studying activities.I suggest that effective measures should be taken to stop the pollution.
第五篇:滄州市普通高中3013-2014學(xué)第一學(xué)期教學(xué)質(zhì)量監(jiān)測(cè)高一數(shù)學(xué)答案
滄州市普通高中2013~2014學(xué)第一學(xué)期教學(xué)質(zhì)量監(jiān)測(cè)
高一數(shù)學(xué)試題參考答案
1.A N={0,3},∴M∩N={0,3}.13πππ22.D coscos(3π=-cos=-.4442
?4-2x>0,?x<2,3.C 由???∴x∈(-1,2). ?x+1>0?x>-1,4.B 選項(xiàng)A周期為2π,選項(xiàng)D不是周期函數(shù),選項(xiàng)C是偶函數(shù),故選B.5.D 2a+b=(4,-2)+(-8,-6)=(-4,-8),由(2a+b)∥c得(-4)×(-4)+8x=0,解得x=-2.1πππ26.C 2sin 15°cos 15°=sin 30°=,A錯(cuò);cos2sin2=cos,B28842
選C.117.B 由f(1)=-1+0=-1<0,f(2)=-+1=,f(1)·f(2)<0,又f(x)在(0,+∞)上為增函數(shù),故函數(shù)f(x)的一個(gè)零22
點(diǎn)在區(qū)間(1,2)上.
33558.A ∵0<a=(0.7<()0=1,b=0.3>()0=1,5533c=log3(log35)<log3(log33)=0,∴c<a<b.55
9.C 記〈a,b〉=θ,∵|a-b|=(a-b)=a-2a·b+b|a|-2|a||b|cos θ+|b|,而|a|3+4=5,|b|=2,∴|a-b|25-2×5×2×cos θ+2=19.1π∴cos θ=θ=.23
1110.A 由a·b=得sin α+cos α= 33
1(sin α+cos α)2=sin2α+cos2α+2sin αcos α=()2,3
118π8得1+sin 2α=,故sin 2α=-1=-,cos(2α+)=-sin 2α=.99929
ππ1π11.B 函數(shù)y=3cos x的圖象向左平移y=3cos(x+,再把橫坐標(biāo)縮小為原來的得到y(tǒng)=3cos(3x+). 3333
12.D ∵f(x)是R上的奇函數(shù),∴f(0)=0,π又f(2015)=f(503×4+3)=f(3)=f(-1)=-f(1)=-sin=-1,2
故f(0)+f(2015)=0-1=-1.13.10 根據(jù)題意知tan α=-63x=10.x511cos=223111=22233,C對(duì).故42
14.-2 由冪函數(shù)的定義知m2-m-5=1,解得m=3或m=-2.若m=3,則m-1=2,不合題意,舍去,∴m=-2.7π33715.cos(α-=sin α=,cos 2α=1-2sin2α=1-2×()2=.2525525
→→→→→→16.10 AO=AB-OB,AO=AC-OC,→→→→→所以2AO=(AB+AC)-(OB+OC),【數(shù)學(xué)試卷·參考答案第1頁(共3頁)】·14-11-79A·
→→→→→→→→所以2AO·BC=(AB+AC)·BC-(OB+OC)·BC
→→→→→→→→=(AB+AC)·(AC-AB)-(OB+OC)·(OC-OB)
→→→→→→=|AC|2-|AB|2-(|OC|2-|OB|2)=|AC|2-|AB|2
→→=36-16=20,所以AO·BC=10.17.解:(1)∵m=-1,∴A={x|-1<x<1},又B={x|-3<x<0},∴A∪B={x|-3<x<1}.(5分)
(2)∵A?B,B={x|-3<x<0},?-3≤m,∴?∴-3≤m≤-2.(10分)?m+2≤0,2sin αcos α+cos α2sin αcos α+cos αcos α(1+2sin α)18.解:f(α)==(6分)1+sinα+sin α-cosα2sinα+sin αsin α(1+2sin α)
∵1+2sin α≠0,∴f(α)=
2π∴f(=3.(12分)61219.解:(1)任取x1,x2∈(0,+∞),且x1<x2,則
111111x-xf(x1)-f(x2)=+-==,ax1ax2x1x2x1·x2
∵0<x1<x2,∴x1·x2>0,x2-x1>0,所以f(x1)-f(x2)>0,即f(x1)>f(x2).
故f(x)在(0,+∞)上單調(diào)遞減.(6分)cos α sin α
?f(2)=1,?a=2,1(2)由(1)知f(x)在[,2]上單調(diào)遞減,?1??5(12分)2f()=mm=?2?2
20.解:(1)由m⊥n?m·n=0,∴(2a-b)·(a+kb)=2a2+(2k-1)a·b-kb2=0,∵|a|(-3)+4=5,a·b=|a|·|b|·cos 60°=5,∴m·n=2×25+(2k-1)×5-4k=0,解得k=-15分)2
(2)若m∥n,則存在實(shí)數(shù)λ使得m=λn,?2a-b=λ(a+kb)=λa+λkb,?2=λ,1又∵a與b的夾角為 60°,∴a與b不共線,則有??k=-.(12分)2?-1=λk,Tπ21.解:(1)由題意知=T=π,ω=2,22
5π5π5π5π又∵f(x)最高點(diǎn)為(3),∴A=3,設(shè)f(x)3sin(2x+φ),將點(diǎn)(3)代入得3=φ),∴sin(+φ)1212126
=1,則5πππππφ=+2kπ,φ2kπ,k∈Z,∵|φ|<,∴φ=- 62323
π故f(x)3sin(2x-).(6分)3
ππ3π(2)2kπ≤2x-2kπ,k∈Z得 232
5π11π+kπ≤x≤+kπ,k∈Z,1212
故f(x)的遞減區(qū)間為[5π11πkπ,+kπ],k∈Z.(12分)1212
?a>0,22.解:(1)∵f(-1)=0,∴a-2b+1=0,又f(x)的值域?yàn)閇0,+∞),∴? 2?Δ=4b-4a=0,∴b2-(2b-1)=0,∴b=1,a=1,∴f(x)=x2+2x+1=(x+1)2.∴F(x)=??(x+1)2,x>0,?-(x+1)2,x<0.(5分)
(2)∵f(x)是偶函數(shù),∴f(x)=ax2+1,F(xiàn)(x)=??ax2+1,x>0,?-ax2-1,x<0,∵m·n<0,不妨設(shè)m>n,則n<0.又m+n<0,-n>m>0,∴|m|<|-n|,F(xiàn)(m)+F(n)=f(m)-f(n)=(am2+1)-an2-1=a(m2-n2)>0,∴F(m)+F(n)不能小于零.(12分)